D. -2p + q - 5 - you have to multiply, then distribute parentheses and apply plus or minus rules.
Using the following equation is how you translate degrees Fahrenheit to Kelvin:
Kelvin = (Fahrenheit + 459.67) * 5 / 9<span>
or you could use:
</span>
Kelvin = (Fahrenheit - 32) * 5 / 9 + 273.15<span> </span>
Answer:
the
Step-by-step explanation:
it's fairly easy actually. You just have to use sin
The answer is A.
When replacing the variable 'x' by 'x + 2' the graph is shifted 2 units to the left. When we replace the variable, the function changes
from

To


And therefore the function is shifted 2 to the left.
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s