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Oksana_A [137]
3 years ago
9

In a ten day period, the probability of a certain number of outbreaks of a contagious viral infection is represented in the

SAT
1 answer:
pogonyaev3 years ago
3 0

e.0.80fodytyffhfjgufddihoggffjkj

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A financial goal that I have is to have a well-paying job as I get out of high school so I can afford to go to a University of my choice. This way I won't be in crippling debt and have to take out massive student loans. However, inflation as well as taxes will influence this. Income taxes will force me to have to give up some of my hard-earned money, which will significantly reduce the amount of money I actually make.
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Even though the process is endothermic, snow can sublime. Which tendency in nature accounts for this phase change?.
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Explanation:

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3 0
2 years ago
C=
wariber [46]
<h2>Right answer: I and II only </h2>

If we already have the formula to find how temperature measured in degrees Fahrenheit, relates to a temperature in degres Celsius:

C=(F-32)\frac{5}{9}    (1)

We can know the formula to find how temperature measured in degrees Celsius, relates to a temperature in degres Fahrenheit, only by isolating F:

F=(\frac{9}{5}C)+32    (2)

Having both formulas, let’s begin:

I) If we want to prove that a temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius:

Beginning with 1\ºF:

C=(1\ºF-32)\frac{5}{9}=-17.22\ºC

This means: 1\ºF=-17.22\ºC

Now we are going to increase 1 degree Farenheit. In other words, we are going to use 2\ºF:

C=(2\ºF-32)\frac{5}{9}=-16.66\ºC

This means: 2\ºF=-16.66\ºC

Calculating the difference between -16.66\ºC   and  -17.22\ºC:

-16.66\ºC-(-17.22\ºC)=0,55\ºC>>>>This is equal to 5/9 degree Celsius, hence is correct

II) If we want to prove that a temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit:

Beginning with 1\ºC:

F=(\frac{9}{5}1\ºC)+32  

F=33.8\ºF  

This means: 1\ºC=33.8\ºF  

Now we are going to increase 1 degree Celsius. In other words, we are going to use 2\ºC:

F=(\frac{9}{5}2\ºC)+32  

F=35.67\ºF  

This means: 2\ºC=35.67\ºF  

Calculating the difference between 35.67\ºF   and  33.8\ºF:

35.67\ºF-33.8\ºF=1.8\ºF>>>>This is a proof of the statement, hence is also correct.

<h2 />

III) If we want to prove that a temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius:

Beginning with 1\ºC:

F=(\frac{9}{5}1\ºC)+32  

F=33.8\ºF  

This means: 1\ºC=33.8\ºF  

Now we are going to add \frac{5}{9}\ºF:

33.8\ºF+\frac{5}{9}\ºF=34.35\ºF

And use this value in the Celsius formula:

C=(34.35\ºF-32)\frac{5}{9}=1.30\ºC

This means: 1.30\ºC=34.35\ºF

In other words: An increase in 5/9 degree Fahrenheit is equivalent to a temperature increase of 1.30 degree Celsius, <u>not 1 degree Celsius</u>.

Therefore this statement is incorrect.

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D. All of the are important features of this model

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