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3 years ago

How can you tell Is something is a unit rate

1 answer:

4 0

Unit rate is a ratio between two different units with a denominator of one. When we divide a fraction's numerator by its denominator, the result is a value in decimal form. For example: 8/4 = 2 and 3/6 = 0.5. When we write numbers in decimal form, we can write them as a ratio with one as the denominator.

For example, we can write 2 as 2/1, and 0.5 as 0.5/1. However, since that approach can be a little clumsy, we usually drop the one. That said, it's important to remember the one is there, especially when working with unit rates.

For instance, 8 miles/4 hours = 2 miles/hour. Notice again that, while we did not include the 1, we did include the unit 'hour' Miles per hour is a familiar expression, as are unit rates such as:

interest/amount invested

revolutions/minute

salary/year

Conversationally, the word ''per'' indicates we are using a unit rate.

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Please answer thank u ASAP.

Neko [114]

Answer:

Step-by-step explanation:

7 0

3 years ago

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

3 0

3 years ago

using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)

REY [17]

Answer:

Midpoint is $(\frac{-37 }{2}, 14)$

Step-by-step explanation:

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

= $(\frac{-11 -26}{2}, \frac{30 - 2 }{2})$

= $(\frac{-37 }{2}, \frac{28 }{2})$

= $(\frac{-37 }{2}, 14)$

Midpoint is (-37/2, 14)

3 0

3 years ago

"Data from the World Health Organization in 2013 were used to predict the life expectancy of men in a country from the life expe

marshall27 [118]

Answer:

The predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

Step-by-step explanation:

The least square regression line is used to predict the value of the dependent variable from an independent variable.

The general form of a least square regression line is:

$\hat y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

The regression line to predict the life expectancy of men in a country from the life expectancy of women in that country is:

$\hat y=3.73 +0.88 x$

Compute the life expectancy of men in a country in which the life expectancy of women is 70 years as follows:

$\hat y=3.73 +0.88 x$

$=3.73 +(0.88\times 70)\\=3.73+61.6\\=65.33$

Thus, the predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

6 0

3 years ago

What is the last calculation that should be done to evaluate 4(8 - 6)5² - 6 ÷ (–3)?

balandron [24]

Answer:

Your answer will be 202.

Step-by-step explanation:

4(8 - 6)5² - 6 ÷ (–3)

(4)(2)(25)+2

200+2

202

7 0

3 years ago