Which of the following is a perfect square?A.) 115B.) 169C.) 154D.) 279

Mathematics

1 answer:

Dvinal [7]2 years ago

7 0

Answer:

B (169)

Step-by-step explanation:

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How do I solve this problem

tino4ka555 [31]

Answer:

0.6

Step-by-step explanation:

2x3 add 1 power of 10 to the 3 you get 6 and now you just remove/divide the power of 10 you added and you get .6

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2 years ago

What is the difference? 4/3 - 7/9 a. - 1/2 b. -1/3 c. 5/9 d 11/12

ANTONII [103]

4/3-7/9

= (36-21) /27

= 15/27

= 5/9 which is C

5 0

2 years ago

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I need help with that

alukav5142 [94]

If i remember correctly.. it’s C, you cant have the X values repeating.

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2 years ago

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Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

2 years ago

g.o. has 3 orange picks for every two green . if there are 25 picks in all , how many picks are orange

mixer [17]

I think 15 are orange and 10 are green

6 0

3 years ago