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3 years ago

you are playing catch with a friend and you are standing 90 feet from him. how many yards away are you standing?

Mathematics

2 answers:

ser-zykov [4K]3 years ago

7 0

1 yard = 3 feet

90 divide by 3 is 30

30 yards

olga2289 [7]3 years ago

4 0

You would be standing 30 Yards away from your friend.

Why?: Because 1 yard is 3 feet.

And 10 yards is 30 feet. So you would do 10 x 3 to get your answer.

Let me know if this helps!

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Only male crickets chirp. They chirp at different rates depending on their species and the temperature of their environment. Sup

bezimeni [28]

Answer:

4920

7084800

2585952000

Step-by-step explanation:

82 chirps = 1 minute

We have 60 minutes in one hour, so 82 x 60 =4920 chirps in one hour

In 24 hours we have 60x24 = 1440 minutes and in one minutes we have 4920 chirps,

Therefore 4920 x 1440 mins =7084800 chirps in one day .

There are 365 days in a year and in one day the cricket chirps 7084800, so 365 days x 7084800 = 258595200 chirps in a year

6 0

3 years ago

6x2 - 5x - 4 is equivalent to:

Sophie [7]

Answer:

(2x + 1) (3x - 4)

Step-by-step explanation:

Solution:

6x² - 5x - 4
6x²- (8 - 3)x - 4
6x²- 8x + 3x - 4
2x (3x - 4) +1 (3x - 4)
(2x + 1) (3x - 4)

4 0

2 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

The expression now have the same denominator

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