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B. 40 fluid ounces of lemonade
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
Answer:
f(x) = (x -3)^2 - 1
Step-by-step explanation:
f(x) = x^2 - 6x + 8
a = 1, b = -6 and c = 8
So we are finding half of the b equation (ignore the negative sign)
Half of 6 is 3, so we are going to square 3 (3^2 = 9) and add 9 to the left side and subtract 9 to the right side
(x) = (x^2 - 6x + 9) + (8 - 9)
You can tell the polynomial is a perfect square, so we will have to factor it using the perfect square method
(x^2 - 6x + 9)
square toot of x^2 is x and square root of 9 is 3 and the operation sign after the a number is a minus sign
(x -3)^2
Don't forget the rest of the equation from before
(x -3)^2 + (8 - 9)
(x -3)^2 - 1
So the equation is f(x) = (x -3)^2 - 1
