Question

The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour. At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
pls pls pls

Answer 1

Answer:

2.174 hours

Step-by-step explanation:

Let the number of hours be represented as:

x

The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour.

$12.79 + $0.11 × x

12.79 + 0.11x

At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour.

$13.29 - $0.12× x

13.29 - 0.12x

Equating both equations together

Stock A = Stock B

12.79 + 0.11x = 13.29 - 0.12x

Collecting like terms

0.11x + 0.12x = 13.29 - 12.79

0.23x = 0.5

x = 0.5/0.23

x = 2.1739130435 hours

x = Approximately = 2.174 hours

If the two rates​ continue, the number of hours that the prices of the two stocks will be the​ same is 2.174 hours