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pickupchik [31]
3 years ago
13

7/4 x 1 = 7/4 x ?/? = 35/20

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

5/5

Step-by-step explanation:

7/4 × 5/5 = 35/2

hole this helps

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Name the constansin the expression <br> 7x + 9y + 3.
alexgriva [62]

Your constant is 3 because it’s alone

5 0
3 years ago
Help with pic below !
Yuliya22 [10]
Because you are shifting the function to the left by 2 units, you will represent that as:

Because you are shifting the function to the left by 2 units, you will represent that as:
f(x) = (x+2)^2-7

Generally, if you are moving to the left, it's seen going in the negative direction, but remember since f(x) is going to the left, it means that you are solving for x. So, solve for x in (x + 2), you get x = -2. Hopefully this makes sense.

The, you are dilating the entire function in which you have to multiply the entire thing. Let's do it:
f(x) = 3((x+2)^2-7)

Which is equal to:
f(x) = 3(x+2)^2 -21

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3 0
3 years ago
2x squared +5x+3=-2x
True [87]
The answer is X= -3 or X=-1/2
4 0
4 years ago
Jesse deposits her $500 into bank. Interest is 9.5%. She withdraws 737.50. How long did she keep her money in the account?
mario62 [17]
We'll need to assume that this is a case of compound interest which is paid once per year.

Then    A = P (1 + r)^t becomes

$737.50 = $500 (1+0.095)^t

Then ($737.50/$500) = 1.095^t

Take the log of both sides.  0.1688 = log 1.095^t, or 
                                             0.1688 = t log 1.095 = t(0.0394)

Solving for t,    t = 0.1688/0.0394 = 4.28 years 

This comes out to 4 years and 28/100 of one year, 
or                           4 years and 3.36 months, or
                               4 years, 3 months and 11 days.
6 0
3 years ago
0.05 is 1/10 the value of <br>A. 5 <br>B. 0.005<br>C. 0.5 <br>D. 50<br>​
anastassius [24]

Answer:

C.

Step-by-step explanation:

as 0.05 is 1/10 of a number, multiplying 0.05 by 10 will give you the number that when divided by 10 will give you 0.05. Hence just multiply 0.05 by 10 and you get 0.5.

8 0
3 years ago
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