For vertical asymptotes, find the values which make the function indetermine in this case x=-7,so this is the only vertical asymptote.
For horizontal asymptotes, find the limit when x tends to infinity:
=(5x/x-15/x)/(2x/x+14/x) = 5/2, this is the horizontal asymptote y=5/2
For obliques, you have to meet the degree of the numerator is exactly a greater degree than the denominator, in this case they are the same degree so no oblique asymptote.
Hello!
To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.
y = log₂ 1/2, y = -1
y = log₂ 1, y = 0
y = log₂ 2, y = 1
y = log₂ 4, y = 2
y = log₂ 8, y = 3
y = log₂ 16, y = 4
Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.
Answer:
See explanation below.
Step-by-step explanation:
Note that in △RST and △UVW
- m∠T=180°-m∠R-m∠S;
- m∠W=180°-m∠U-m∠V.
Since ∠R≅∠U and ∠S≅∠V, then ∠T≅∠W.
In ΔRST and ΔUVW:
- ∠S≅∠V (given);
- ∠T≅∠W (proved);
- ST≅VW (given).
ASA theorem that states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
By ASA theorem ΔRST≅ΔUVW.
