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Marat540 [252]
3 years ago
12

Find the 6th term of the geometric sequence whose common ratio is

Mathematics
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

-3072

Step-by-step explanation:

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<h2>B) (0, 6)</h2>

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For question 4 the Y needs to be by itself. So instead of it being x+2y>/-12 it would be y>/-6+x. You would have to subtract x on both sides and then divide 2 on both sides as well. whatever you do on one side, you have to do it on the other side. Hope this helps. After you redo all the equations, you graph them. If you need anymore help , let me know!

4 0
3 years ago
Paul has 12 coins in his pocket, consisting entirely of dimes and quarters. If he has a total of 195 cents in coins, how many co
anyanavicka [17]

Let x be the number of dimes

and y be the number of quarters

Total number of coins = 12

So number of dimes + number of quarters = total number of coins

x + y = 12 ---------> equation 1

We know, 1 Quarter = 25 cents, 1 Dime = 10 cents, total cents = 196

y quarters = 25y cents , x dimes = 10x cents

x dimes + y quarters = 195 cents

10x + 25y = 195 -----------> equation 2

Now solve both equations

x + y =12, we solve for y by subtracting x on both sides

y = 12-x

Now substitute y in second equation

10x + 25(12-x) = 195

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-15x = -105 ( divide by -15)

x=7

y= 12-x

y=12-7 = 5

The number of dimes = 7

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8 0
3 years ago
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