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Kryger [21]
3 years ago
13

What best describes how the parameter c is related to the period of the function?

Mathematics
1 answer:
ioda3 years ago
5 0

Answer:

Is there a picture?

Step-by-step explanation:

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Find the missing length of the triangle
lana [24]

Answer:

37

Step-by-step explanation:

the formula for this is:

A^2 + B^2 = C^2

if you substitute them:

12^2 + 35^2 =C^2 -> 144+ 1225= 1369

and the square root of 1369 is 37

hope this helps!!!

4 0
3 years ago
Please help! I need to get these questions done, you don't have to answer all of them
melomori [17]

Answer:

2/60 I think

Step-by-step explanation:


8 0
3 years ago
Please HELP! Remember to SHOW YOUR WORK! Thx
Katena32 [7]
25 35 25

25...35...25
4 0
3 years ago
The price of one gallion of heating oil $2.589. Which is this number rounded to the nearest penny A $2.50 a $2.59 c $2.70 $3.00​
FromTheMoon [43]
$2.59 would be the correct rounding because you look at the 8 and the number next to it is 9 so the 8 goes up to nine since it’s larger than 5
5 0
3 years ago
Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

6 0
3 years ago
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