The values of a and b are 4 & 6
It would be H because 13 has no factors other than 1, and 13.
Hope this helps!
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Answer:
14
Step-by-step explanation:
64-8=56
56/4=14
