3 years ago

These topics don’t seem for me to understand one bit, can I get help on this?

Mathematics

1 answer:

Andrew [12]3 years ago

3 0

Answer:

v=5

plug it in I dare you

Step-by-step explanation:

Nah set 4v+44 = 9v-31 bc of some property I forgot the name of, then simplify from there.

You might be interested in

what is the length of the side of a right triangle that has a hypotenuse that is 15 mm and a side of 9 mm

ratelena [41]

C) 27 mm
Hope this helps

4 0

3 years ago

I'm almost completely out of points. Pls answer this. I don't get it

Mars2501 [29]

10. Factor form: 2(x+5)x(x+1)

11. Factor: (x-4)x(x-10)

12. Factor: (a-8b)x(a+8b)

Hope this helps! ❤️

7 0

3 years ago

Read 2 more answers

Hi! can someone help me find the value of x?

Furkat [3]

Answer:

x=2

Step-by-step explanation:

Since the angles are equal, the side lengths are equal (isosceles triangle)

12 =6x

Divide by 6

12/6 = 6x/6

2= x

5 0

3 years ago

The half-life of uranium-238 is 4.5x10^9 years. The half-life of uranium-234 is 2.5x10^5 years. How many times greater is the ha

lara31 [8.8K]

Answer:

Half-life of uranium-238 $18 \times 10^{3} \text { times greater }$ that of uranium-234

Explanation:

Half time of uranium-238 = $4.5\times 10^9$ years

Half time of Uranium-234 = $2.5\times 10^5$ years

To find how much times greater the half life of uranium-238 is from uranium-234

= $\frac{\text { Half life of Uranium-238 }}{\text { Half time of Uranium - 234 }}$

= $\frac{4.5 \times 10^{9}}{2.5 \times 10^{5}}$

= $18 \times 10^{3} \text { times greater }$

Hence Uranium-238 is $18 \times 10^{3} \text { times greater }$ than Uranium-234

4 0

4 years ago

Roberto is a systems analyst. His annual salary is $165,125. What is his monthly salary?

lilavasa [31]

Answer: it is 13,760.416

Step-by-step explanation:

If you divide his annual salary by 12 months you get your answer which is $13,760.416

4 0

3 years ago

Read 2 more answers