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3 years ago

Simplify the expression to a+bi form: (-6-10i)(2-3i)

Mathematics

2 answers:

Fantom [35]3 years ago

7 0

Answer:

-42-2i

Step-by-step explanation:

MA_775_DIABLO [31]3 years ago

4 0

So the answer is -42-2i

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Volume Quiz help!!!!!!

Kay [80]

Answer:

134.0cm3

Step-by-step explanation:

v=pi r2*h/3

=16 pi*8/3

=134.0 cm3

8 0

3 years ago

Read 2 more answers

The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 107 kilometers, and the distance of planet Venus from the Sun

slega [8]

Answer:

5.2

Step-by-step explanation:

distance(Mercury, Sun) = 5.8 x 10^7

distance(Venus, Sun) = 1.1 x 10^8

distance(Venus, Mars) = 1.1 x 10^8 - 5.8 x 10^7

The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

simply subtract 5.8 from 11.0.

This gives us a result of 5.2 x 10^7.

6 0

4 years ago

Read 2 more answers

Using the right triangle below find the cosine of angle A.

svetlana [45]

For the given triangle, the cosine of angle A equals $\frac{1}{2}$ .

Step-by-step explanation:

Step 1; In the given triangle, the opposite side has a length of 9 units, the adjacent side has a length of 3√3 units while the hypotenuse of the triangle measures 6√3 units. To calculate the cosine of angle A we divide the adjacent side by the hypotenuse side.

cos A = $\frac{adjacent side}{hypotenuse}$ .

Step 2; Length of the adjacent side = 3√3 units.

Length of the hypotenuse side = 6√3 units.

cos A = 3√3 / 6√3

cos A = $\frac{1}{2}$ .

To check we also have A = 60° and cos 60° = $\frac{1}{2}$ .

4 0

4 years ago

Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].

Vilka [71]

The average value is given by

$\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt$

Setting $y=\cos5t$ , you get $\mathrm dy=-5\sin5t\,\mathrm dt$ , and the integral becomes

$\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy$
$=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}$
$=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145$

6 0

4 years ago

Saturn's rings extend to about 120,000 kilometers above Saturn's equator. Saturn's diameter at its equator is also about 120,000

Allisa [31]

Answer:

1130400 km

Step-by-step explanation:

We know the formula for circumference of a circle:

Circumference = $2\pi r$

So we need the radius of Saturn ring to calculate its circumference.

We are given Saturn's diamter which is 120,000km; and know that Saturn's ring extends for about 120,000 km from the circumference of the Saturn.

Therefore, the radius of Saturn's ring will be 120000 km plus half of the diameter of Saturn:

Radius of Saturn's ring = 120000 + (120000/2) = 180000 km

Circumference of Saturn's rings = 2 x 3.14 x 180000 = 1130400 km

3 0

4 years ago