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Orlov [11]
3 years ago
7

For f(x) =8x+11, find f(x) when x = 4.

Mathematics
2 answers:
Juliette [100K]3 years ago
5 0

Answer:

43

Step-by-step explanation:

f(x) = 8x + 11

x = 4

f(4) = 8(4) + 11

f(4) = 32 + 11

f(4) = 43

Rufina [12.5K]3 years ago
3 0

Answer:

43

Step-by-step explanation:

Plug x in.

8(4)+11=32+11=43

Hope I helped!

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What is the graph of y= 3/4x - 3
alexira [117]
-3 is the y intercept, so place a point there. The slope is 3/4. So from your -3 point, go up 3 and over 4. Make a point. Do that another time and also from the -3 intercept go down 3 and over left 4, the. you’ve got yourself a nice line.

4 0
3 years ago
you rent a canoe for 5$ per hour.Your cost before the tax is added is 12.50. write and solve an equation to find the total numbe
Basile [38]

Answer: The equation is   5x = 12.50   and  you will have the canoe for 2 and half hours or 2 hours 30 minutes.

Step-by-step explanation:

You rent the canoe for 5 dollars per hour and that can be represented by the expression  5x.  After sometime you paid $12.50 meaning that to find the number of hours that you need the canoe, we need to set 5x to equal 12.50.

5x  = 12.50    Solve for x  by divide both sides by 5.

x = 2.5

This means you will need the canoe for 2 and half hours.

8 0
3 years ago
Tevon,leah,and beth are playing a computer game. Trevon scored -8. Beth's score was 3/4 of trever's score, and leah's score was
faust18 [17]

Answer:

Trevon scored -8.

Beth's score was 3/4 of trever's score = -8 *3/4 = -6

leah's score was 1/4 of beth's score. = -6 *1/4 = -1.5

Leah's score was -1.5


8 0
4 years ago
-77.35 in a fraction
nikitadnepr [17]
-77 and 7/20 is the answer simplified and without it being simplified you get -77 and 35/100
8 0
3 years ago
the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle
nikdorinn [45]
l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}
length\approx9.71cm;\ width\approx17.71cm
4 0
3 years ago
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