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3 years ago

Can All mixed numbers can be renamed as decimals?

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

Answer:

We can convert a mixed number (or mixed fraction) to a decimal. Strategies to convert mixed fractions to decimals: Change the mixed fraction to an improper fraction and then divide. Convert the fractional part only and then add it to the whole number.

ZanzabumX [31]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

Any mixed number that you have, is really the whole number and a set amount of fractions behind it.

If you have 3 $\frac{6}{9}$ , then you can change that to 3.6666.... If you have 1 $\frac{1}{2}$ , then you can change that to 1.5.

Hope that this helps!

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1.<br> If b is bigger than a, what can you tell me about angle A?

amm1812

Answer:

a is smaller than b

Step-by-step explanation:

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3 years ago

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Leasees number from least to greatest 0.5 and 3/16 and 0.5 and 5/48

kumpel [21]

0.5;0.5;3/
16;5/48 that would be how to do it

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4 years ago

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A true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn

Makovka662 [10]

<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

$H_0: p=0.50$

$H_a: p>0.50$ , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : $\dfrac{52}{80}=0.65$

Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68$

P-value : $P(z>2.68)=0.0037$ [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

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4 years ago

N x 3/8 = 1 What is N?

Dominik [7]

Answer:

$N=\frac{8}{3}$

Step-by-step explanation:

The image below shows step-by-step on how to solve it.

Hope this helps! :)

7 0

3 years ago

when the polynomial f(x) is divided by (x-2) the remainder is 4, and when it is divided by (x-3) the remainder is 7. Given that

natima [27]

$f(x)=(x-2)(x-3)Q(x)+ax+b$

Recall the polynomial remainder theorem: the remainder upon dividing a polynomial $p(x)$ by $x-c$ is equal to $p(c)$ . This means that $f(2)=4$ and $f(3)=7$ , which tell us

$4=2a+b$

$7=3a+b$

From here we can solve for $a,b$ :

$4=2a+b\implies b=4-2a$

$7=3a+b=3a+(4-2a)\implies a=3\implies b=-2$

so that

$f(x)=(x-2)(x-3)Q(x)+3x-2$

Now,

$\dfrac{f(x)}{(x-2)(x-3)}=Q(x)+\dfrac{3x-2}{(x-2)(x-3)}$

so the remainder upon dividing $f(x)$ by $(x-2)(x-3)$ is $3x-2$ .

Next, if $f$ is a cubic function, then $Q(x)$ is a linear polynomial that can be written as $Q(x)=cx-d$ . The coefficient of $x^3$ in $f(x)$ is 1 (unity), so that expanding $f(x)$ gives us