Answer:
-0.0526
Step-by-step explanation:
Let X be the random variable denoting the net gain(in dollars) for a single trial(one bet).
Assuming that each number in the wheel is equally likely, probability of the outcome being a victory is
and probability of failure is
. For a win, X takes value 35 and for a loss X takes value -1. So the model is,
![P(X=35) = \frac{1}{38}](https://tex.z-dn.net/?f=%20P%28X%3D35%29%20%3D%20%5Cfrac%7B1%7D%7B38%7D%20)
![P(X=-1) = \frac{37}{38}](https://tex.z-dn.net/?f=%20P%28X%3D-1%29%20%3D%20%5Cfrac%7B37%7D%7B38%7D%20)
![P(X=i) = 0 \;if\; i \neq 38, i\neq -1](https://tex.z-dn.net/?f=%20P%28X%3Di%29%20%3D%200%20%5C%3Bif%5C%3B%20i%20%5Cneq%2038%2C%20i%5Cneq%20-1%20)
The mean for one bet is ![E(X) = \sum xP(X=x) = 35\times\frac{1}{38} - 1\times\frac{37}{38} = -0.0526](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%20%5Csum%20xP%28X%3Dx%29%20%3D%2035%5Ctimes%5Cfrac%7B1%7D%7B38%7D%20-%201%5Ctimes%5Cfrac%7B37%7D%7B38%7D%20%3D%20-0.0526%20)
2/4 is the fraction with the greatest value...
<h2>
Answer:</h2><h2>-16 -6.</h2><h2 /><h2>
-2(5+3)(-2+4)</h2><h2>
-2(8) (-6)</h2><h2>
Then multiply the one's outside with the one's in the bracket.</h2><h2>
Making it...</h2><h2>
-16 -6</h2>
-18
1) Distribute the -6 to the parentheses
-4 - (6*7) - (-6*3)
2) Simplify
-4 - 42 + 18
-18
Answer:
y - 5 = 3(x - 2)
y - 5 = 3x - 6
y = 3x - 1
Second Option.
Step-by-step explanation: