I use edge also most of the answers come for this app all u have to do is copy and paste your answer hopefully this helps
Answer:
Before coming back up to the surface the maximum depth, Cassidy went was 6.25 ft. below the water surface
Step-by-step explanation:
The height of Cassidy's diving platform above the water = 6 ft.
The equation that models her dive is d = x² - 7·x + 6
Where;
d = Her vertical position or distance from the water surface
x = Here horizontal distance from the platform
At Cassidy's maximum depth, we have;
dd/dx = d(x² - 7·x + 6)/dx = 2·x - 7 = 0
x = 7/2 = 3.5
∴ At Cassidy's maximum depth, x = 3.5 ft.
The maximum depth,
= d(3.5) = 3.5² - 7 × 3.5 + 6 = -6.25
The maximum depth, Cassidy went before coming back up to the surface =
= -6.25 ft = 6.25 ft. below the surface of the water.
Step-by-step explanation:
It's an irrational number.
![\sqrt[3]{275:7}=\sqrt[3]{\dfrac{275}{7}}=\dfrac{\sqrt[3]{275}}{\sqrt[3]{7}}=\dfrac{\sqrt[3]{275}\cdot\sqrt[3]{7^2}}{\sqrt[3]{7}\cdot\sqrt[3]{7^2}}=\dfrac{\sqrt[3]{275\cdot49}}{\sqrt[3]{7\cdot7^2}}\\\\=\dfrac{\sqrt[3]{13475}}{\sqrt[3]{7^3}}=\dfrac{\sqrt[3]{13475}}{7}=\dfrac{1}{7}\sqrt[3]{13475}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B275%3A7%7D%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B275%7D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%5Ccdot49%7D%7D%7B%5Csqrt%5B3%5D%7B7%5Ccdot7%5E2%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B%5Csqrt%5B3%5D%7B7%5E3%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B7%7D%3D%5Cdfrac%7B1%7D%7B7%7D%5Csqrt%5B3%5D%7B13475%7D)
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Answer:
Option C
Z=8
Step-by-step explanation:
5z-8=32
Rearranging the equation
5z-8+8=32+8
5z=40
Z=40/5
Z=8