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3 years ago

I don’t know how to solve these can someone explain ?

Mathematics

2 answers:

Anastasy [175]3 years ago

6 0

first u should find the area of rectangular:

7 × 16 = 112

then u should find the area of triangular:

Altitude = 13- 7 = 6

base=16 - 8 = 8

so...u can find the area of triangular now:

(6× 8)÷2 = 48 ÷ 2 = 24

so...the area of your shape is: 112+ 24 = 136

mojhsa [17]3 years ago

3 0

The answer is 136 :)

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3 years ago

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3 years ago

Polygon ABCD has the following vertices: A(−3, 3), B(5, 5), C(5, −4), and D(−3, −4) Calculate the area of the polygon.

aniked [119]

To solve this problem you must apply the proccedure shown below:

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3 years ago

Read 2 more answers

Can someone please help I really need these points

spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to the product of two segments of second chord.

In the given circle,

$AE\times CE=BE\times DE$

$(3x-11)\times (5x-4)=(x+2)\times (-x+17)$

$15x^2-12x-55x+44=-x^2+17x-2x+34$

$15x^2-67x+44+x^2-15x-34=0$

$16x^2-82x+10=0$

Divide both sides by 2.

$8x^2-41x+5=0$

Splitting the middle term, we get

$8x^2-40x-x+5=0$

$8x(x-5)-1(x-5)=0$

$(8x-1)(x-5)=0$

Using zero product property, we get

$(8x-1)=0$ or $(x-5)=0$

$x=\dfrac{1}{8}$ or $x=5$

For $x=\dfrac{1}{8}$ , the side AE is negative. So, $x=\dfrac{1}{8}$ is not possible.

Therefore, the required solution is $x=5$ .

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3 years ago