Use the equation of motion under gravity:-
s = 16t^2 where s is the distance and t = time
2063 = 16t^2
t^2 = 2063 / 16 = 128.94 s
t = sqrt 128.94 = 11. 4 seconds to the nearest tenth of a second
2(3x-1) >=4x-6
6x-2>=4x-6
6x-4x>= -6+2
2x>=-4
x>=-2
You can see after simplification, the valve of x can be any number greater than or equal to -2. i.e -5 and -3 can not be in the solution set. the first choice can be dismissed, the fact the variable O could be any number that may not satisfy the solution. Therefore 0-1 is the answer, any thing between 0 & 1 including 0 and one satisfy the solution set
We have that Clarence sells yearly subscriptions to a particular magazine.
He sells at least 10 and not more than 25 subscriptions each week.
The function f(t) = 48t represents the amount of money earned for selling t subscriptions each week.
So;
10 ≤ t ≤ 25
f(t) therefore is 48(10) ≤ f(t) ≤ 48(25)
This gives: 480 ≤ f(t) ≤ 1200
So the amount of money earned f(t) for selling t subscriptions each week is all multiples of 48 between 480 and 1200, inclusive.
Answer:
283
Step-by-step explanation:
