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lubasha [3.4K]
2 years ago
15

I will give the correct answer brainliest !!

Mathematics
1 answer:
zubka84 [21]2 years ago
6 0

why do they be giving us this hardwork :(

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you purchased paint for the rooms in your house you have 1.5 cans of paint left you painted for rooms in each room required 2 ca
Leona [35]

Answer:

10

Step-by-step explanation:

I may be wrong but if each of the four rooms required two cans, 4x2 is 8. then it says you spilt half a can, making that 8.5 cans. but, you have 1.5 cans left. 8.5+1.5= 10.

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3 years ago
What's the formula length and area with work plz!
dem82 [27]
You would have to put them into different shapes and the formula for the squares is sides^2 and the formula for the triangles is 1/2(b*h), eventually you will add the numbers together
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3 years ago
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9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
What solid can be folded from the net?
Novosadov [1.4K]

Answer:

I think it is triangular prisim

3 0
2 years ago
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How do you write -5 1/100 as a decimal?
White raven [17]

Answer:

The answer is -5.01

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3 years ago
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