I will give the correct answer brainliest !!

choli [55]

N in (-oo:+oo)

-13 = n-8 // - n-8

8-n-13 = 0

-n-5 = 0 // + 5

-n = 5 // * -1

n = -5

n = -5

3 0

3 years ago

Nathan invests money in an account paying simple interest. He invests $180 and no money is added or removed from the investment.

sweet-ann [11.9K]

I think this question is technically asking
196.20 is what percent of 180, if so it would be 109%

https://www.percentagecal.com/answer/180-is-what-percent-of-196

5 0

2 years ago

Read 2 more answers

Rearrange the formula to make t the subject: S=d/t

Virty [35]

Answer:

t = d/S

Step-by-step explanation:

S = d/t

Cross multiply

S x t = d

Divide both sides by S

S/S x t = d/S

t = d/S

4 0

3 years ago

1. a) if 60%% students passed in Physics, 55% pass in Math and 40% fail in both subjects, what percent of students are pass in b

hammer [34]

Answer:

75%

Step-by-step explanation:

Percent. of students passed who in physics =60% Percent. of students who passed in maths = 55%

Total percent. who passed = (60+55)%

= 115%

Percent. of students who failed= 40%

Percent. of students who passed = (115 - 40)%

= 75%.

please mark me as brainliest , pleaseeeeeeeeeeplease

5 0

2 years ago

Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

8 0

3 years ago