Find the axis of symmetry and vertex of y=-2x^3+8

Which of the following are incorrect expressions for slope? Check all that apply.

Crazy boy [7]

Pretty sure it’s B and D

7 0

2 years ago

PLEASE HELP FOR TEST will mark brainiest !!

sdas [7]

Answer:

552.920307 yd^2 or 552.92 yd^2 for sigfigs

Step-by-step explanation:

basically you take the area of the entire circle and subtract the interior circle to leave the ring and that’s your answer

so the area formula of a circle is π r^2

the radius (r) is just half the diameter so the entire diameter is 48 so the radius is 24 - π(24)^2 = 1809.557368^2

then the interior circle’s diameter is 40 so the radius is 20 - π(20)^2 = 1256.637061^2

so now it’s just subtraction:

1809.557368 yd^2 - 1256.637061 yd^2 =
552.920307 yd^2 or 552.92 yd^2 for sigfigs

hope this helps :)

6 0

2 years ago

Read 2 more answers

2. Match the shapes given to their correct areas.

aliina [53]

Applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

a. The shape given is a square.

Area of the square = $s^2$

Where,

s = 11.6 yd

Plug in the value of s

Area of the square = $11.6^2 = 134.6 $ yd^2$

b. The shape given is a circle.

Area of the circle = $\pi r^2$

Where,

r = 12 cm

Plug in the value of r

Area of the square = $\pi \times 12^2 = 452.2 $ cm^2$

c. The shape given is a parallelogram.

Area of the parallelogram = $bh$

Where,

b = 7 cm

h = 5.8 cm

Plug in the value of b and h

Area of the parallelogram = $7 \times 5.8 = 40.6 $ cm^2$

d. The shape given is a rectangle.

Area of the rectangle = $l \times w$

Where,

l = 8.3 ft

w = 5.2 ft

Plug in the value of l and w

Area of the rectangle = $8.3 \times 5.2 = 43.2 $ ft^2$

e. The shape given is a trapezium.

Area of the trapezium = $\frac{1}{2} (a + b) \times h$

Where,

a = 2.8 m

b = 10.4 m

h = 3.9 m

Plug in the value of a, b, and h

Area of the trapezium = $\frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 $ m^2$

f. The shape given is a triangle. (See attachment for the shape).

Area of the triangle = $\frac{1}{2} \times b \times h$

Where,

b = 9 ft

h = 4.8 ft

Plug in the value of b, and h

Area of the triangle = $\frac{1}{2} \times 9 \times 4.8 = 21.6 $ ft^2$

Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

Learn more here:

brainly.com/question/22560863

5 0

2 years ago

What is the range of the function f(x) = 3x2 + 6x – 8?

timama [110]

Answer:

Range is {y | y ≥ –11}

Step-by-step explanation:

This is quadratic equation.

A quadratic equation's range can be found if we find the vertex.

For quadratic equations that have a positive number in front of $x^{2}$ , it is upward opening and thus all the numbers greater than or equal to the minimum value of vertex is the range.

The formula for vertex of a parabola is:

Vertex = $(-\frac{b}{2a}, f(-\frac{b}{2a})$

Where,

$a$ is the coefficient of $x^{2}$
$b$ is the coefficient of $x$

From our equation given, $a=3$ and $b=6$

Now, $x$ coordinate of vertex is $x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1$

$y$ coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the $x$ value [ $x=-1$ ] into the equation. So we have: