Answer:
30
Step-by-step explanation:
Answer:
Step-by-step explanation:
1)a) Abscissa of O 0
Abscissa of A 4
Abscissa of B -3 {opposite of 3}
Abscissa of C 3 {3 is the only positive integer like A}
Abscissa of D -4.5
Abscissa of E -6
Abscissa of F -1 {Midpoint of AE = (6+4)/2 = 10/2 = 5th number from -6 or 4}
b) OB = 3 units
DA = 8.5 {4.5 +4 = 8.5}
Answer:
n<50
Step-by-step explanation:
7/2*5n + 14<49
7n/2*5+14<49
(7n)+(2*5)14/2*5 <49
7n+10*14/2*5 <49
7n+140/2*5 <49
7n+140/10 <49
7n+140 < 10*49
7n+140 < 490
(7n+140)+(-140)<490+(-140)
7n+140-140<490-140
7n<350
7n/7 < 350/7
n<2*5^2*7/7
n<2*5^2
n<2*25
n<50
<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable
which is the smaller number. Accordingly, the lager number will be
given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

So:
1. The sum of 2 consecutive integers can be written as:

2. Nine times the smaller and 5 times the larger can be written as:

Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:


The two numbers are:

a.

is a proper joint density function if, over its support,
is non-negative and the integral of
is 1. The first condition is easily met as long as
. To meet the second condition, we require

b. Find the marginal joint density of
and
by integrating the joint density with respect to
:


Then


c. This probability can be found by simply integrating the joint density:

