Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3
Side 2 and side 3 are the longer two congruent sides
Add up the three sides and set them equal to the given perimeter of 33. Solve for x
(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5
If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)
Answer: 13 inches
Answer:what do u need help with?
Step-by-step explanation:
Let the two numbers be x and y.
Let m = the fraction (or percentage) for increasing the numbers.
Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36
Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36
Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0
Answer: 0.
The difference between the two numbers is zero.
Answer:
2/7.
Step--step explanation:
1/2 * 4/7.
Multiply the numerators and the denominators:
= 1*4 / 2*7
= 4 / 14 Now divide numerator and denominator by 2:
= 2/7.
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show
Let 
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D)
.
So, we can write the given integral as
Splitting up terms and replacing 
in the first integral, we get
