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LekaFEV [45]
3 years ago
6

WILL GIVE BRAINLIEST!!

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

c is the answer

Step-by-step explanation:

arlik [135]3 years ago
7 0

Answer:

C

Step-by-step explanation:

First move the term -1 to the other side. When you do that, it should be changed into +1, and since this is inequality change the ≤ to ≥ (negative numbers when moved must flip the inequality direction)

so you get x ≥ 6 + 1

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What is this answer please
Arisa [49]

Answer:

The correct answer is B.

Step-by-step explanation:

4 0
3 years ago
Which of the following satisfy x ≥ 4.1? Select all that apply.
natta225 [31]

Answer:

x = 4.5

x = 4.1

Step-by-step explanation:

3 0
2 years ago
Evaluate the function.<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20-%20x%5E%7B2%7D%20%20-%207x%20-%205" id="TexForm
Nat2105 [25]
<h3>Answer:  5</h3>

===================================================

Explanation:

Everywhere you see an x, replace it with -5. Then use the order of operations PEMDAS to simplify

f(x) = -x^2 - 7x - 5\\\\f(-5) = -(-5)^2 - 7(-5) - 5\\\\f(-5) = -(25) - 7(-5) - 5\\\\f(-5) = -25 + 35 - 5\\\\f(-5) = 10 - 5\\\\f(-5) = 5\\\\

Keep in mind that for the x^2 term, you are squaring all of x = -5, which includes the negative as well. So that means

x^2 = (-5)^2 = (-5)*(-5) = 25

but sticking a negative out front makes

-x^2 = -(-5)^2 = -25

6 0
3 years ago
Simplify for ez fast points!
soldier1979 [14.2K]

Answer:

0.027

Step-by-step explanation:

0.1×0.1×0.1=0.027----->2.7×10^-2

6 0
3 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0
3 years ago
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