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d1i1m1o1n [39]
3 years ago
11

Please help if you can ! what is the sum or difference 6y^5-9y^5

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0

Answer:

The sum or difference of 6y^5-9y^5\ is\ -3y^5

Step-by-step explanation:

We have to find the sum or difference 6y^5-9y^5

      6y^5-9y^5\\\\=(6-9)y^5\\\\=-3y^5

Hence, the sum or difference of 6y^5-9y^5\ is\ -3y^5

Vinvika [58]3 years ago
3 0
The difference of that eqation is to -3y^5
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3 years ago
How to solve this (b) ???​
vladimir1956 [14]

(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]

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= [{5^(2x+1)}/{6×5^x}]

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(c). 4a³b²

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2 years ago
Ophelia has 5 flower less than Daisy. Together they have 20 flowers. How many flowers have each of them?
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3 years ago
a square of area is 36 cm squared is cut to make two triangles, A and B. The ratio of area A to area B is 2:1. Work out the dime
weeeeeb [17]

Dimensions of:

Rectangle A are 6 cm by 4 cm.

Rectangles B are 6 cm by 2 cm.

Step-by-step explanation:

It is given that:

The area of square is 36 cm^2.

Hence, the side of the square is given as:

Area=(side)²

36=(side)²

side=6

Hence, the side of square is 6 cm.

Now, as the area of two rectangles A and B are in the ratio:

2:1

This means that, the area of rectangle A is 24 cm².

and area of rectangle B is 12 cm²

( Since, 36/(2+1)=36/3=12

Area of rectangle A=2×12=24 cm²

Area of rectangle B=1×12=12 cm². )

Hence, the dimensions of A are:

6 cm by 4 cm.

and the dimensions of rectangle B are:

6 cm by 2 cm.

8 0
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