9514 1404 393
Answer:
54 = 2 × 3³
36 = 2² × 3²
Step-by-step explanation:
The term "factors" can mean different things in this context. Usually, it means "prime factors." Exponents are used to indicate the number of times a factor is repeated. The prime factors of these numbers are ...
54 = 2 × 3³
36 = 2² × 3²
__
Sometimes, we use the word "factors" to mean "positive integer divisors." The number of divisors is the product of the exponents of the prime factors, each increased by 1. That is, 54 has (2·4) = 8 divisors; 36 has (3·3) = 9 divisors. The odd number of divisors is one indication that the number is a perfect square.
The divisors of these numbers are ...
54 is divisible by 1, 2, 3, 6, 9, 18, 27, 54
36 is divisible by 1, 2, 3, 4, 6, 9, 12, 18, 36
Answer:
We need a sample size of least 119
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Sample size needed
At least n, in which n is found when 
We don't know the proportion, so we use 
, which is when we would need the largest sample size.
Rounding up
We need a sample size of least 119
Answer:
I believe the answer is D.
Step-by-step explanation:
The Answer makes sense.
Answer:
simple interest= 5100
using formula SI=<u> </u><u>PTR</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>100
hope it helps..
have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.
before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43
sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===
or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
