Here L = W, but H can be different.
The sum L+H+W must be less than or equal to 192 cm.
We can solve L + H + W = 192 for H: H = 192 - W - L. Remembering that W = L, the formula for H becomes 192 - 2W.
The formula for volume would be V = L*W*H.
This becomes V = W*W*H, or V = W^2*(192-2W)
Multiplying this out: V = w^2*192 - 2W^3
Two ways of determining W:
1) graph V = 192W^2 - 2W^3 and determine the value of W at which V is at a max with the constraint W + L + H is equal to or smaller than 192.
2) Differentiate V with respect to W and set the result equal to zero:
384W - 6W^2 = 0. Solving for W: W(384 - 6W) = 0.
W = 0 is trivial, so just solve 384 - 6W = 0 for W: 6W = 384, and W = 64.
The width is 64 cm, the length is 64 cm also, and the height is (192-2W) cm, or 64 cm.
These dimensions produce the max volume.
You're answer is Major Arc.
Attached is a screenshot of spreadsheet used to do this problem.
You will see the excel functions used for each column. The average score is highlighted in blue.
So you would at most 1500 minus 100, then use pemdas to solve.
Answer:
52
Step-by-step explanation:
Evaluting an expression basically means to multiply the numbers given.
In this certain question, we are just multiplying 13 by 4 which would give us the result of 52.