The spring .2m far when it is compressed on being supported by a mass of 10kg.
Given: Mass of 30 kg which compresses spring by 0.6m
To find: The compression of the spring when it is supported by a mass of 10 kg
Concept: Compression springs are coiled springs that hold mechanical energy in a compressed state. When these springs are subjected to compressive loads, they compress and shorten, capturing and storing significant potential force.
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
By using unitary method,
10 is 3 times less than 30.
so, 30/3=10
Also applying the same proportion over the lengths compressed,
we get, 0.6/3=.2
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Answer:
23.78 feet remaining
Step-by-step explanation:
34.5-10.72=23.78
Answer:
a = 4 and b = - 30
Step-by-step explanation:
Expand the left side and compare like terms on both sides, that is
(x + 2)(x - 3)(x + 5) ← expand the first pair of factors using FOIL
= (x² - x - 6)(x + 5) ← distribute
= x³ + 5x² - x² - 5x - 6x - 30 ← collect like terms
= x³ + 4x² - 11x - 30
Compare like terms with x³ +ax² - 11x + b
4x² and ax² ⇒ a = 4
+ b and - 30 ⇒ b = - 30
