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Lynna [10]
2 years ago
9

2x – y=8

Mathematics
1 answer:
emmasim [6.3K]2 years ago
5 0

Answer:

the answer is D no solution

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For what values of h and k does the linear system have infinitely many solutions? 2x1 + 5x2 = −1 hx1 + kx2 = 7
Kruka [31]

Answer:

The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

Step-by-step explanation:

Let 2\cdot x_{1}+5\cdot x_{2} = -1\cdot h\cdot x_{1} + k\cdot x_{2} = 7, if this linear system has infinitely many solutions, then the following conditions must be met:

-1\cdot h = 2 and k = 5.

h = -2 and k = 5

The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

4 0
2 years ago
A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters,
tino4ka555 [31]
You answer would be 80 cm^2
7 0
3 years ago
When there is a wedge between private costs and social costs, which of the following must be present?
Bogdan [553]
The negative externalities must be present.
4 0
2 years ago
Question is in the pictures.
Kipish [7]
<h3>Answer:</h3>

x/tan(x) is an even function

sec(x)/x is an odd function

<h3>Explanation:</h3>

<em>x/tan(x)</em>

For f(x) = x/tan(x), consider f(-x).

... f(-x) = -x/tan(-x)

Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...

... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)

The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.

_____

<em>sec(x)/x</em>

For g(x) = sec(x)/x, consider g(-x).

... g(-x) = sec(-x)/(-x)

Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...

... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)

The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.

6 0
2 years ago
A certain prescription drug diminishes in the system at a rate of 25% per hour. If a person was administered 1450mg of the drug,
Helen [10]

9514 1404 393

Answer:

  • 459 mg
  • about 20 hours

Step-by-step explanation:

The decay factor is 1 -25% = 0.75 per hour, so the exponential equation can be written ...

  r(t) = 1450·0.75^t . . . . . milligrams remaining after t hours

__

a) After 4 hours, the amount remaining is ...

  r(4) = 1450·0.75^4 ≈ 458.79 . . . mg

About 459 mg will remain after 4 hours.

__

b) To find the time it takes before the amount remaining is less than 5 mg, we need to solve ...

  r(t) < 5

  1450·0.75^t < 5 . . . . use the function definition

  0.75^t < 5/1450 . . . . divide by 1450

  t·log(0.75) < log(1/290) . . . . . take logarithms (reduce fraction)

  t > log(1/290)/log(0.75) . . . . . divide by the (negative) coefficient of t

  t > 19.708

It will take about 20 hours for the amount of the drug remaining to be less than 5 mg.

7 0
2 years ago
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