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denis-greek [22]
3 years ago
15

What are 3 powers of 64?

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

64 = 1 x 64, 2 x 32, 4 x 16, or 8 x 8.

Hope that helps!

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URGENT A dance competition on television had five elimination rounds. After each elimination, only one-fourth of the contestants
trapecia [35]

Answer:

Use the idea of slope here to find the rate of change of contestants since that is what slope is: the average rate of change between two coordinates. This is not linear, so the rate of change for the whole function is not going to be the same as it is between round 2 and round 4. The slope formula using the coordinates from x = 2 to x = 4 is 8 - 128/4 - 2 which gives a slope of -60. This represents the average rate of change of contestants from the second round to the fourth.

6 0
3 years ago
Read 2 more answers
An auditorium has 30 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. How many seat
Nezavi [6.7K]

Answer:

1170

Step-by-step explanation:

start with 10 and add 2 to each row. Then add each number up when you have 30 numbers.

10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44, 46,48,

50,52,54,56,58,60,62,64,66,68.

You get 1170 seats total.

I know there is a type of equation that can be used but I wanted to be 1000 percent sure of my answer to you to be correct.

8 0
3 years ago
nick have collection of 80 cars.3/5 of his toys are bus.the rest are cars and bike.the number of cars are the three time the num
stiks02 [169]

Answer:

24 cars

Step-by-step explanation:

out of 80 toys, 3/5 are buses- 80 * 3/5 is 48 so there are 48 buses

80 - 48 is 32, 32 of the rest of the toys are cars and bikes

we know that there are 3 times as many cars than bikes, so to find out how many cars and bikes there we can do 3n + n, where n is the number of bikes it also equals 4n

32 = 4n; n = 8

there are 8 bikes, so there are 24 cars

8 0
3 years ago
Work out the balance for 1500 invested for 2 years at 3.7% per annum.
Andru [333]
1500 x 1.037 = 1555.50
1555.50 x 1.037 = 1613.05
8 0
3 years ago
How do you create a truth table to prove that for any statement, p,~(~p) equals p?
Fynjy0 [20]
If p is true, then \sim p is false, which in turn means \sim(\sim p) is true.

If p is false, then \sim p is true, and so \sim(\sim p) is false.

So, because p\equiv\sim(\sim p) in both cases, the statement is a tautology (always true).

If you were to put this in a table, you would have one column each for p,\sim p,\sim(\sim p). In the first column (p) you can think of p as an independent variable that can only take two values, true and false. In the next column (\sim p), you would negate the value in the previous column. And so on.

It should roughly look like this:

p ... ~p ... ~(~p)
T ...  F  ...    T
F ...  T  ...    F
3 0
4 years ago
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