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denis-greek [22]
2 years ago
15

What are 3 powers of 64?

Mathematics
1 answer:
andrew11 [14]2 years ago
4 0

Answer:

64 = 1 x 64, 2 x 32, 4 x 16, or 8 x 8.

Hope that helps!

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There are 6 Programmers and 8 Analysts working on a team at CIA. What is the unsimplified ratio of Programmers to Analysts?
Rzqust [24]

Answer:  \dfrac{6}{8}

Step-by-step explanation:

Given

There are 6 Programmers and 8 Analysts working on a team at CIA.

Ratio of Programmers to analysts is

\Rightarrow \dfrac{6}{8}

Un-simplified ratio is \dfrac{6}{8}

Simplified ratio is \dfrac{3}{4}

6 0
2 years ago
Simplify the square root of 29 divided by the square root of 58
3241004551 [841]
I got 0.7071067812

Hope this helps
7 0
3 years ago
What fractions are equivalent to 1.27 repeated
kramer
<span>Let x equal your repeating decimal. Call this equation x = 1.273
</span><span>Multiply both sides of your previous expressions by 100. Call this equation 100x = 127.273
</span><span>Subtract 1 from both sides of the equation to get 99x = 126.
</span><span>Divide both sides of the equation by 99 to get 126/99.
</span><span>126/99 reduced is to its lowest terms is 1 and 3/11.
</span>
3 0
3 years ago
If the price is increasing at a rate of 2 dollars per month when the price is 10 dollars, find the rate of change of the demand.
densk [106]

Answer:

The demand reduces by $7.12 per month

<em></em>

Step-by-step explanation:

Given

p\to price

x \to demand

2x^2+5xp+50p^2=24800.

p =10; \frac{dp}{dt} = 2

Required

Determine the rate of change of demand

We have:

2x^2+5xp+50p^2=24800.

Differentiate with respect to time

4x\frac{dx}{dt} + 5x\frac{dp}{dt} + 5p\frac{dx}{dt} + 100p\frac{dp}{dt} = 0

Collect like terms

4x\frac{dx}{dt} + 5p\frac{dx}{dt} = -5x\frac{dp}{dt}  - 100p\frac{dp}{dt}

Factorize

\frac{dx}{dt}(4x + 5p) = -5(x  + 20p)\frac{dp}{dt}

Solve for dx/dt

\frac{dx}{dt} = -\frac{5(x  + 20p)}{4x + 5p}\cdot \frac{dp}{dt}

Given that: 2x^2+5xp+50p^2=24800. and p = 10

Solve for x

2x^2 + 5x * 10 + 50 * 10^2 = 24800

2x^2 + 50x + 5000 = 24800

Equate to 0

2x^2 + 50x + 5000 - 24800 =0

2x^2 + 50x -19800 =0

Using a quadratic calculator, we have:

x \approx -113\ and\ x\approx88

Demand must be greater than 0;

So: x=88

So, we have: x=88; p =10; \frac{dp}{dt} = 2

The rate of change of demand is:

\frac{dx}{dt} = -\frac{5(88  + 20*10)}{4*88 + 5*10} * 2

\frac{dx}{dt} = -\frac{5(288)}{402} * 2

\frac{dx}{dt} = -\frac{2880}{402}

\frac{dx}{dt} \approx -7.16

<em>This implies that the demand reduces by $7.12 per month</em>

8 0
3 years ago
How many solutions does have the quadratic equation 5x^2+6x+6=0
Lapatulllka [165]
2

To determine the number of solutions in an equation, look at the exponent with the biggest value

4 0
2 years ago
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