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solong [7]
3 years ago
6

Which graph represents the solution to the compound inequality? –6 < 3x – 12 ≤ 9

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

second graph

Step-by-step explanation:

Solving the inequality

- 6 < 3x - 12 ≤ 9 ( add 12 to all 3 intervals )

6 < 3x ≤ 21 ( divide the intervals by 3 )

2 < x ≤ 7

The graph has an open circle at 2 and a closed circle at 7

This is represented on the second graph

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The ___ of a parabola is the line, along with a point not on the line, which is used to generate a parabola.
enot [183]

Answer:

Directrix

Step-by-step explanation:

The <u>directrix</u> of a parabola is the line, along with a point not on the line (which is the <em>focus</em>), which is used to generate a parabola.  The <em>directrix</em> is parallel either to the x- or y-axis, and is perpedicular to the parabola's axis of symmetry (at x = h).      

Therefore, the correct answer is "<u>directrix</u>."  

3 0
2 years ago
Solve for x if the angles are 110 and 2x+3
katen-ka-za [31]

Answer:

x=16

Step-by-step explanation:

Because this is an isosceles triangle the angle 2x+3 is the same as the missing angle. The angles in triangles add up to 180 degrees. 180-110=70.

Because the two angles are the same you can divide 70 by 2 to get 35.

35=2x+3.

35-3=2x+3-3

32=2x

32/2=2x/2

16=x

7 0
3 years ago
Read 2 more answers
8x-6y=54 in slope intercept form please!!
NikAS [45]

Answer: y= 4/3x-9

Step-by-step explanation:

4 0
3 years ago
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3 0
2 years ago
Given: PSTK is a trapezoid, m∠P=90° SK =13, PK = 12, ST=8 Find: The area of PSTK.
guajiro [1.7K]
<h3>Given</h3>

trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8

<h3>Find</h3>

the area of PSTK

<h3>Solution</h3>

It helps to draw a diagram.

∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as

... KS² = PS² + KP²

... 13² = PS² + 12²

... PS = √(169 -144) = 5

This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is

... A = (1/2)(b1 +b2)h

... A = (1/2)(12 +8)·5

... A = 50

The area of trapezoid PSTK is 50 square units.

5 0
3 years ago
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