Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor = 
or
The z factor = 
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
Answer:
-8 = m-2+b
-2 = m-0+b
4 = m2+b
10 = m4+b
Step-by-step explanation:
You just put them in y = mx+b format
Area of the Base = 6 * side^2 / 4 * tan (180/6)
Area of the Base = 6 * 16 / 4 * 0.57735
Area of the Base = 96 / 2.3094
Area of the Base = 41.5692387633
Area of 1 Face = 2 * 6 = 12
Area of 6 Faces = 72
Total Area = 41.5692387633 + 72
Total Area = 113.5692387633
Answer:
Step-by-step explanation:
Refer to file. Trying something different. Should be easier to read than text format and is easier than mathML.
49 is a square of 7 and 4 is a square of 2. To get 45 you need to subtract 7² and 2². Therefore, its the difference of squares.
