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3 years ago

Need help with this question I don't understand.

Mathematics

2 answers:

laila [671]3 years ago

6 0

Answer:

A, B, and C

Step-by-step explanation:

For each value of the x plotted in the graph there can be only 1 y-value, according to the definition of a function.

The circle shown in the last picture isn't a function since there are two y-values plotted on each 1 x-value.

- For example in the last graph, if looked at the point (1,0), this is an x-value, there are 2 y-values (1,6) and (1, -6) for that value.

Hope this helped!

pochemuha3 years ago

3 0

Answer:

Step-by-step explanation:

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Answer:

The answer is 24

Step-by-step explanation:

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Brut [27]

Answer:

±1,±1/3,±5,±5/3,±25,±25/3

Step-by-step explanation:

Rational roots test (p/q)

p= factors of constant

q= factors of number with highest degree

In this equation, the number with the highest degree (power) is 3.

The factors of 3 are 3 and 1.

The constant term is 25.

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3 years ago

An estate of $686,000 is left to three siblings. The eldest receives 2 times as much as the youngest. The middle sibling receive

gregori [183]

Answer:

The oldest gets -> $335,500

The middle gets -> $182,750

The youngest gets -> $167,750

Step-by-step explanation:

Step 1: Make an equation

686,000 = 2y + (15,000 + y) + y

Step 2: Solve for y

686,000 - 15,000 = 2y + 15,000 + y + y - 15,000

671000 / 4 = 4y / 4

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Step 3: Figure the amount of money the middle sibling gets

m = y + 15,000

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m = 182,750

Step 4: Figure the amount of money the oldest sibling gets

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o = 335,500

Answer: The oldest gets -> $335,500

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The youngest gets -> $167,750

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3 years ago

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FromTheMoon [43]

Answer:

The solution set can be given as:

$\{x|x\ \epsilon\ R,x\neq -3\}$

Step-by-step explanation:

Given function:

$f(x)=\frac{1}{2x+6}$

To find the domain of the function in set notation.

Solution:

For the function $f(x)$ to exist the denominator must be ≠ 0

We have the denominator $(2x+6)$ which cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function $f(x)$ will not exist when:

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Solving for $x$

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$\{x|x\ \epsilon\ R,x\neq -3\}$

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