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MA_775_DIABLO [31]
2 years ago
11

Find the smallest number such that the remainder is 3 when it is divided by 16,20 or 24.​

Mathematics
1 answer:
schepotkina [342]2 years ago
4 0

Answer: 123

Step-by-step explanation:

Foe us to solve this, we have to find the lowest common multiple of 16, 20 and 24 first and then add 3 to the LCM. This goes thus:

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

Multiples of 20 = 20, 40, 60, 80, 10, 120, 140, 160

Multiples of 24 = 24, 48, 72, 96, 120

Therefore, the Lowe's common multiple is 120.

We then add the remainder of 3 and this will give:

= 120 + 3

= 123

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