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MA_775_DIABLO [31]
3 years ago
11

Find the smallest number such that the remainder is 3 when it is divided by 16,20 or 24.​

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer: 123

Step-by-step explanation:

Foe us to solve this, we have to find the lowest common multiple of 16, 20 and 24 first and then add 3 to the LCM. This goes thus:

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

Multiples of 20 = 20, 40, 60, 80, 10, 120, 140, 160

Multiples of 24 = 24, 48, 72, 96, 120

Therefore, the Lowe's common multiple is 120.

We then add the remainder of 3 and this will give:

= 120 + 3

= 123

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The measure of acute angle A to the nearest tenth of a degree is 51.2°

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From the given information, we are to determine the measure of the angle.

The angle we are to determine its measure is acute angle A

From the given information, we have that

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Using calculator

A = 51.1965°

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<h3><u>Expla</u><u>nation</u><u> </u><u>:</u></h3>

Let the numbers be x and x + 1.

From the given information,

\dashrightarrow\sf \ \ \ x^2 + (x + 1)^2 = 41 \\  \\  \\

\dashrightarrow\sf \ \ \ 2 {x}^{2}  + 2x + 1 = 41 \\  \\  \\

\dashrightarrow\sf \ \ \ 2 {x}^{2}  + 2x + 1 - 41=0 \\  \\  \\

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\dashrightarrow\sf \ \ \ { \underline{ \boxed{ \bf{ \red{x =  - 5,4}}}}} \ \bigstar \\  \\

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