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musickatia [10]
3 years ago
6

An experiment involves rolling a die and drawing a card from a standard deck of 52 cards.What is the probability that the die la

nds on an even number and the card is a club?
Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer:

the probability of the die landing on 4 is 4/6 or 1/3 and the probability of the card drawn from the deck is a heart is 13/52 or 1/4.

Step-by-step explanation:

fenix001 [56]3 years ago
4 0

Answer:

Assuming a fair die (all faces have equal probability of outcome) which has six different sides then ,

the probability that drawing an 8 and rolling a 7 is :

p( drawing an 8 ) = 4 / 52.

p( rolling a 7 from 6 sided dice ) = 0.

then since both events are independent then their probability is the product of their own probabilities.

p( drawing an 8 ) * p( rolling a 7 from 6 sided dice ) = 4 / 52 * 0 = 0

Assuming fair dice which 7 different sides then ,

p( rolling a 7 from 7 sided dice ) = 1/7.

p( drawing an 8 ) * p( rolling a 7 from 7 sided dice ) = 4 / 52 * 1/7 = 0.010989

Conclusion : assuming its A fair die then , these cases may be possible:

case 1 : < 7 if the number of sides of the die is less than 7 then the probability is zero.

case 2 : =7 if the number of sides of the die is exactly 7 then the probability is 0.010989

case 3 : > 7 if the number of sides of the die is greater than 7 then probability is 4/52 * 1/n where n is number of sides .

Step-by-step explanation:

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Fudgin [204]

Answer:

20

Step-by-step explanation:

7 0
3 years ago
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A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
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Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

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3 years ago
The table shows the results of a survey of seventh-grade students in the lunch-line
Anni [7]

Answer:

D

Look at the picture. :)

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Which of the following phrases can be used to represent -11? the opposite of -11 eleven greater than zero eleven below zero posi
Rama09 [41]

Answer:

the opposite of -11 eleven greater than zero eleven below zero positive eleven

Step-by-step explanation:

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