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wariber [46]
3 years ago
12

Simplify the following: * 9 – 13 Your answer

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0
*******. -4 **********













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What are the x- and y-intercepts for a line with one point at (2,1) and another at (6,3)?​
OverLord2011 [107]

Answer:

x - intercept = 0 and y - intercept = 0

Step-by-step explanation:

Using the two point slope intercept form, the formula is;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

We are given the intercepts to be at

(2,1) and (6,3).

So, x1 = 2 and x2 = 6,while y1 = 1 and y2 = 3

Plugging into the equation, we have;

(y - 1)/(x - 2) = (3 - 1)/(6 - 2)

(y - 1)/(x - 2) = 2/4

(y - 1)/(x - 2) = 1/2

Cross multiply to get;

2(y - 1) = x - 2

2y - 2 = x - 2

2y = x

Now, the x intercept will occur at y = 0.

Thus,

2(0) = x

x = 0

Also, the y intercept occurs when x = 0.

So, 2y = 0

y = 0

x - intercept occurs at (0,0) and y - intercept occurs at (0,0)

5 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
Can anyone help me with these three questions
iren2701 [21]
Sure, what are the questions?
5 0
3 years ago
1+7 (1 - 3b)<br>1+7 (1-3b)
Sergio [31]
It is 16 minus 42b. (16 - 42b)
8 0
3 years ago
8: Two supplementary angles have measurements of (3x)" and (10x - 15)°. What are the measures of the
otez555 [7]

Answer:

45 and 135 A

Step-by-step explanation:

3x + (10x - 15) = 180

5 0
3 years ago
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