Answer:
12 x^4 + 18 x^3 - 9 x^2 thus D is the correct answer.
Step-by-step explanation:
Expand the following:
3 x^2 (4 x^2 + 6 x - 3)
3 x^2 (4 x^2 + 6 x - 3) = 3 x^2 (4 x^2) + 3 x^2 (6 x) + 3 x^2 (-3):
3 4 x^2 x^2 + 3 6 x^2 x - 3 3 x^2
3 (-3) = -9:
3 4 x^2 x^2 + 3 6 x^2 x + -9 x^2
3 x^2×6 x = 3 x^(2 + 1)×6:
3 4 x^2 x^2 + 3×6 x^(2 + 1) - 9 x^2
2 + 1 = 3:
3 4 x^2 x^2 + 3 6 x^3 - 9 x^2
3×6 = 18:
3 4 x^2 x^2 + 18 x^3 - 9 x^2
3 x^2×4 x^2 = 3 x^4×4:
3×4 x^4 + 18 x^3 - 9 x^2
3×4 = 12:
Answer: 12 x^4 + 18 x^3 - 9 x^2
Answer:
The probability that a car that comes into the garage needs both an oil change and a tire rotation is 
.
Step-by-step explanation:
The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:
Denote the events as follows:
<em>X</em> = cars brought in for service need an oil change
<em>Y</em> = cars brought in for service need a tire rotation
The information provided is:
Compute the value of P (X ∩ Y) as follows:
Thus, the probability that a car that comes into the garage needs both an oil change and a tire rotation is .
Answer:
2(w-8) +2w=52
its perimeter so u multiply everything by 2 and since u dont know the length but know its 8 less u subtract by width
Y=mx + b
3x-4y=12
4y=3x-12
y=3/4x-3
when x = 0, y = -3
when y = 0, x = 4
Hope this helps.
Answer:
Step-by-step explanation:
This a categorical data because the sampled responses can't be expressed in exact numerical value but rather the data is in the five categories
