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Tanzania [10]
3 years ago
8

Do you have to be in hard mode in terraria to make the timeless traverler vanity set

Computers and Technology
1 answer:
BabaBlast [244]3 years ago
4 0
Answer: it can only be crafted in corruption world unless you create an artificial corruption biome.
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State Whether the given statement are TRUE OR FALSE. 13X1=13
Naddika [18.5K]

Answer:

true

Explanation:

because everyone know that 13x1=13

7 0
3 years ago
Match each word to its correct meaning.
seropon [69]
1. goes to C.

2. goes to B.

3. goes to A.
6 0
3 years ago
A large institution, such as a bank, may have thousands of transactions to process in which no user interaction is required; whi
White raven [17]

Answer:

Mainframe Computer System

Explanation:

Mainframe systems or simply mainframes are computers used for critical application, bulk processing and transaction processing.

They are larger than the basic computers we find around. They are advantageous as they are able to process large data faster. For this reason, large institutions like banks tend to use them for processing of data because of the thousands of transactions they engage in.

They are capable of handling and processing very large amount of data quickly.

Examples of other large institutions that uses mainframe computers apart from Bank stated in the question are

1. Stock brokerage firms

2. Government agencies

3. Insurance agencies

4. Fortune 500 companies and so on.

6 0
3 years ago
Read 2 more answers
// PrintStrings // Traverse the 2D character array "strings" and print each of the contained strings.// See the example outputs
anzhelika [568]

Answer:

C++.

Explanation:

void printStrings(char strings[NUM_STRINGS][STRING_LENGTH]) {

   // Multi dimension array can be traversed through multi-level loops

   for (int i = 0; i < NUM_STRINGS; i++) {

       for (int j = 0; j < STRING_LENGTH; j++) {

           cout<<"<<strings[i][j]<<";

       }

       cout<<endl;

   }

}

Output would be like this, depending on the size of NUM_STRINGS;

"One"

"Two"

"Three"

....

6 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
4 years ago
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