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Lynna [10]
3 years ago
10

Need help -1/2 + (3/4X4/9)=

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

-\frac{1}{6}

Step-by-step explanation:

In order to find the answer to this question you must use order of operations and add after finding the common denominator.

-\frac{1}{2} +(\frac{3}{4} \times\frac{4}{9} )

P goes first

\frac{3}{4} \times\frac{4}{9}

Solve:

3\times4=12

4\times9=36

=\frac{12}{36}

Reduce:

12\div6=2

36\div6=6

2\div2=1

6\div2=3

=\frac{1}{3}

-\frac{1}{2} +\frac{1}{3}=\frac{-1\times3}{2\times3} +\frac{1\times2}{3\times2} =-\frac{1}{6}

=-\frac{1}{6}

Hope this helps.

Agata [3.3K]3 years ago
4 0

Answer:

The correct answer would be negative 1 over 6 also written as -1/6

Step-by-step explanation:

HAVE A GOOD DAY!

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A sociologist wants to determine if the life expectancy of people in africa is less than the life expectancy of people in asia.
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Answer:

The sample statistics are attached.

First, we need to determine the hypothesis.

The null hypothesis should be: H_{o} : u_{africa} \geq u_{asia}.

The alternative hypothesis should be: H_{a}: u_{africa}

The next step is about calculating the<em> t statistics </em>based on the samples. This <em>t test </em>will give the probability value or p-value, which determines if there's enough to reject the null hypothesis. The formula we need to use to find the t-value is: t=\frac{x_{1}-x_{2}  }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }

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Therefore, the t-value is -3.2.

Now, we using a level of significance of 0.01, and a degree of freedom (df) of 34, we use the t-table to find the p-value for this results. (df = N -1; in this case, we take the smaller sample, which is 35, giving us 34 of df).

Therefore, according to the table attached, <em>the p-value is less than 0.01,</em> which is less than our level of significance. This result means that the null hypothesis is rejected. In other words, there's enough evidence to say that <em>the life expectancy of people in Africa is less than the life of expectancy of people in Asia.</em>

<em></em>

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