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3 years ago

7

Find the range of the function:

1 answer:

-BARSIC- [3]3 years ago

8 0

F(x) = x + 2
when x = 1, f(1) = 1 + 2 = 3
Therefore range for x ≠ 1 is y ≠ 3.

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2 For each figure, are 21 and 22 adjacent angles or vertical angles? Explain.<br> b.<br> a.<br> 2

kupik [55]

Answer:

a is vertical and b is adjacent angles

3 0

3 years ago

Find three consecutive integers whose sum is six times the greater integer

Zepler [3.9K]

3 times 6 18 and do that 6 times add

4 0

3 years ago

How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

3 years ago

Carl worked six and one-half hours on Monday. He worked eight and two-third hours on Tuesday. How many hours did Carl work in al

Gnoma [55]

Answer: 15 hours and 37 minutes

Step-by-step explanation: 6 and 1/2 hours is 6 hours and 30 mins

8 and 2/3 hours is 8 hours and 67 mins

So 8 hours + 6 hours is 14 hours

Since 67 minutes is over an hour, we're going to take 60 minutes from 67, leaving u with 7 minutes

Add the 60 minutes to the 14 hours and you get 15 hours.

Take the 7 minutes and add it to the 30 minutes and you get 37 minutes.

All together the answer is 15 hours and 37 minutes

7 0

3 years ago

For the value of the constant n is Q(x)=x^3+(n-9)x^2+(2n-5)x+4 divisible by(x+4)?

Anestetic [448]

Answer:

no, the constant n is not divisible by (x-4)

3 0

3 years ago