(3.5, 2.5)
i multiplied the original coordinates by the scale factor to get the coordinates of hg. hope this helps :)
Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Answer:
childs ticket is 4 the adult is 3
Step-by-step explanation:
The perimeter of the rectangle will be given by the equation 2(x₂-x₁)+2(y₂-y₁).
<h3>What is the perimeter?</h3>
The perimeter is defined as the sum of all the sides of the figure. Here in the question, we have the rectangle with coordinates (x₁,y₁),(x₂,y₂),(x₂,y₁)(x₂,y₂).
So by using the distance formula we will find the length and width of the rectangle.
![l=\sqrt{x_2-x_1)^2+(y_1-y_1)^2}](https://tex.z-dn.net/?f=l%3D%5Csqrt%7Bx_2-x_1%29%5E2%2B%28y_1-y_1%29%5E2%7D)
![l=\sqrt{(x_2-x_1)^2}](https://tex.z-dn.net/?f=l%3D%5Csqrt%7B%28x_2-x_1%29%5E2%7D)
l=x₂-x₁
Width of the rectangle is given by
![w=\sqrt{x_2-x_2)^2+(y_1-y_1)^2}](https://tex.z-dn.net/?f=w%3D%5Csqrt%7Bx_2-x_2%29%5E2%2B%28y_1-y_1%29%5E2%7D)
![w=\sqrt{(y_2-y_1)^2}](https://tex.z-dn.net/?f=w%3D%5Csqrt%7B%28y_2-y_1%29%5E2%7D)
w=(y₂-y₁)
Hence, the perimeter of the rectangle is given by
P=2l+2w
P=2(x₂-x₁)+2(y₂-y₁)
To know more about perimeter follow
brainly.com/question/19819849
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