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Natali [406]
2 years ago
7

Given f(x) = 8x-15, find x when f(x) =9

Mathematics
1 answer:
lawyer [7]2 years ago
3 0

Answer:

72-15 = 57

Step-by-step explanation:

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Hello! answer Pls, No links.. (13 points and brainiest if i can).
Eva8 [605]
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8 0
3 years ago
A high school teacher gives three regular exams during a semester and one final exam at the end of the semester. A student’s fin
statuscvo [17]
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.

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5 0
2 years ago
What is the radius of a circle with a circumference of 30.4 feet? 4.8ft 3.4ft 6.3ft 9.7ft?
tankabanditka [31]
≈<span>4.8 ft is your answer</span>
7 0
3 years ago
A multivitamin tablet contains 0.13g of vitamin C. How much vitamin C does a bottle of 20 tablets contain? Write your answer in
Digiron [165]

Answer:

2600mg

Step-by-step explanation:

0.13*20=2.6g

2.6g=2600mg

7 0
2 years ago
Statuary Hall is an elliptical room in the United States Capitol in Washington, D.C. The room is also called the Whispering Gall
dalvyx [7]

Answer: a) \frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1

b) The distance of two foci is 85.4 feet

c) Area = 3502.67 square feet

Step-by-step explanation: a) An ellipse has the equation in the form of:

\frac{x^{2} }{a^{2} }+\frac{y^{2} }{b^{2} } = 1, where a is the horizontal axis and b is the vertical axis.

For the Statuary Hall, a = \frac{97}{2} = 48.5 and b = \frac{46}{2} = 23, so the equation will be

\frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1.

b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:

a^{2} = b^{2} + c^{2}

c^{2} = a^{2} - b^{2}

c = \sqrt{48.5^{2} - 23^{2} }

c = 42.7

The distance is 2c, so 2·42.7 = 85.4 feet.

The two foci are 85.4 feet apart.

c)The area of an ellipse is given by:

A = a.b.π

A = 48.5 · 23 · 3.14

A = 3502.67 ft²

The area of the floor room is 3502.67ft².

3 0
3 years ago
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