A plane leaves the airport at 9:15pm and travels at speed 560km/h then at midnight plane will be at 1540 km far away.
As given,
Plane leaves the airport at 9:15 pm
Plane travels at speed of 560 km /h
Total time = 2hour+ 45minutes
= 2hour+ (45/60)hour
= (11 /4) hour
We have
1 hour = 560 km
⇒ (11 /4)hour = (560 ×11)/4 km
= 1540 km
Therefore, a plane leaves the airport at 9:15pm and travels at speed 560km/h then at midnight plane will be at 1540 km far away.
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63$ your answer it’s pretty straight forward and simple
Answer:
y= -
+2
I hope this correct and helped! :)
Step-by-step explanation:
Slope intercept: y=mx+b
x+3y=6
Subtract x on both sides
3y=-x+6
Divide by 3 on each side.
y= -+2
Answer:
you want to be a friend se you want me to be a good
The answer would be -2k -30
