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3 years ago

Plz answer this :) 10 pionts

Mathematics

1 answer:

kari74 [83]3 years ago

3 0

Answer: Well... this is a long question.

1. All are moving 7 units to the left.

2. A = 0, B = 1 east, C = 1 east and 8 south, D = 8 south.

3. A = 0, B = 26 east, C = 26 east and 8 south, 8 east and 8 south.

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Yesenia drove 45.3 miles on Monday and 3.8

kondor19780726 [428]

Answer:

The answer is 49.1

Step-by-step explanation:

45.3 + 3.8 = 49.1

8 0

2 years ago

A triangle with sides of lengths 16, 63, and 65 is a right triangle.

malfutka [58]

False I think it doesn't add up to 18

3 0

3 years ago

angle c is the complement of angle 1, and angle s is the supplement of angle 1. what is the difference between the measures of a

Nataliya [291]

Hey there,

Your question/statement states: Angle $C$ is the complement of angle $1$ , and angle $S$ is the supplement of angle $1$ . what is the difference between the measures of angle $S$ and angle $C$

There is not difference between angle $S$ and $C$ The reason why would be because they both are congruent to angel $1$ . If they are both congruent to that angel, then they are both the same shape. One thing that could be the problem is that they may be a different size. Yes they can be a same shape, but there size if different. But, based on what the little excerpt above, I believe that both $S \ and \ C$ are the same.

Hope this helps.
~Jurgen

6 0

4 years ago

Read 2 more answers

The sum of the masses of two heavyweight boxers is 190kg. ⅘ the heavier boxer is 10kg less than the mass of lighter boxer. Find

ratelena [41]

Answer:

Their masses are 100 kg and 90 kg

Step-by-step explanation:

Equations

We'll solve the problem by setting only one variable. Let's call:

x = weight of the heavier boxer

Since the sum of the masses of both boxers is 190 Kg:

190 - x = mass of the lighter boxer.

It's given that $\frac{4}{5}$ of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:

$\displaystyle \frac{4}{5}x=190-x-10$

Operating:

$\displaystyle \frac{4}{5}x=180-x$

Multiplying by 5:

$\displaystyle 4x=5(180-x)$

$\displaystyle 4x=5*180-5x$

Simplifying:

$\displaystyle 9x=900$

$x=\frac{900}{9}=100$

The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.

Their masses are 100 kg and 90 kg

5 0

3 years ago

Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let X = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = p = 0.05.

The sample of items selected is of size, n = 150.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.05.

According to the Central limit theorem, if a sample of large size (n > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a z-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago