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saul85 [17]
3 years ago
13

Which statement describes the meaning of the point (0,10) on the graph?

Mathematics
2 answers:
Flura [38]3 years ago
6 0

Answer:

10

Step-by-step explanation: You would probably have to multiply it out to find out the equation.

marusya05 [52]3 years ago
5 0

Answer:

If there are answer choices i would need to see them

Step-by-step explanation:

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11. There are a total of 30 puzzle pieces. Three
natulia [17]

Answer: 2

Step-by-step explanation:

5-3=2

30-5=15

6 0
3 years ago
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7th grade math I need help with this
Rina8888 [55]

Answer:

each bag of candy is $6.00

Step-by-step explanation:

1 bag would cost $6.00

1×$6.00=$6.00

6 bags × $6.00 = $36.00

7 0
3 years ago
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A population of 130,000 grows 4% per year for 16 years.
alexgriva [62]

Let's consider the scenario after each year:

After the zeroth year, the population is: 120 000(1 + 0.04)⁰

After the first year, the population is: 120 000(1 + 0.04)¹

After the second year, the population is: 120 000(1 + 0.04)²

...

Thus, we can find the general rule:

After the nth year, the population is: 120 000(1 + 0.04)ⁿ

And after the 16th year, the population is 120 000(1 + 0.04)¹⁶ = 224 758 (rounded to nearest whole number)

6 0
3 years ago
The probability distribution for a random variable x is given in the table. -5 -3 -2 0 2 3 Probability .17 .13 33 16 11 10 Find
IgorLugansk [536]

Answer:

0.79

Step-by-step explanation:

add up the probability that is less than or equal to  0, which is 0.17+0.13+0.33+0.16 = 0.79

5 0
3 years ago
The monthy net gains sales for a new sporting goods store were: $7195, $1484, $3224, $8807, $7185, $1730, $2573, $7071, $5360, S
brilliants [131]

Answer:

$7,185 see below ↓

explanation:

With median, it is about the number that appears the most, and since the closest it gets is between $7,071 and $7,195, we have to pick the number that averages in-between which in this case is <em>7,185.</em>

Below, this ↓ array proves the logic.

<em />\left[\begin{array}{ccc}7195&7185&7071\end{array}\right]

5 0
3 years ago
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