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2 years ago

12

Which representation of a transformation on a coordinate grid does not preserve congruence?

1 answer:

Ghella [55]2 years ago

6 0

The second one time for me a little kid I got the wrong thing to say I was

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Reflect the point (8,-7) across the x-axis

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. The temperature on Monday was −5∘C . By Tuesday the temperature rose to −2∘C. Find the change in temperature.

Alekssandra [29.7K]

Answer: $3^{\circ}C$

Step-by-step explanation:

Given

The temperature on Monday was $-5^{\circ}C$

By Tuesday, it becomes $-2^{\circ}C$

Change in temperature is the difference between the two temperatures.

$\Rightarrow \Delta T=-2-(-5)\\\Rightarrow \Delta T=-2+5\\\Rightarrow \Delta T=3^{\circ}C$

Therefore, the change in temperature is $3^{\circ}C$ .

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2 years ago

What number is 15 % of 45.4 ?

Fantom [35]

15% of 45.4=6.81 this is the final answer

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2 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

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