Answer:
def my_sqrt(a):
while True:
x = a
y = (x + a / x) / 2
if (y == x):
break
else:
x = y
print(x)
return 0
my_sqrt(5)
Explanation:
The above is a function in Python, and the exact copy as code of what is being given in the question. Its a method to find out the square root of a number which is a here. The while loop has been used as being mentioned in the question, and the variables are defined and calculated as being stated.
def summation (num1, num2):
i = 0
for x in range (num1 : num2 + 1):
i += x
return i
print ( summation(l, r))
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