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olganol [36]
3 years ago
9

Which of these angles can replace x in tan (x)?

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

C. φ

Step-by-step explanation:

tan \phi \:  =  \frac{6}{5}  \\  \\ tan x \:  =  \frac{6}{5}  \\  \implies \: x =  \phi

Thus \Phi can replace x

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Answer:

Find each measure. 9. NP. ANSWER: 14. 10. PS.

Step-by-step explanation:

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Read the passages given and answer the questions in complete sentences to identify the literary techniques used.
sergij07 [2.7K]

Answer:Passage: Also, he gives the impression that it was only he who really climbed it on his own, and that he then practically pulled me, so that I “finally collapsed exhausted at the top, like a giant fish when it has just been hauled from the sea after a terrible struggle.” Since then I have heard plenty about that “fish,” and I admit I do not like it.

Step-by-step explanation:

Everest—the prestige of Everest AND Nor is it for Hillary

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3 years ago
Exercise 5.2. Suppose that X has moment generating function
soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Step-by-step explanation:

Given:

moment generating function  of X as:

MX(t) = \frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}

a)  Now

Mean, E(X) = M_{X}'(t=0)

Thus,

M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}

or

M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}

also,

E(X^{2})=M_{X}''(t=0)

Thus,

M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}

or

M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}

Therefore,

Mean, E(X) = M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}

or

Mean, E(X) = - 0.5

and

E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}

or

E(X^{2}) = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Therefore,

at x = 0, P(x) = \frac{1}{2}

at x= - 4 ,P(x) = \frac{1}{3}

at x = 5, P(x) = \frac{1}{6}

Thus,

E(X) =\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})

or

E(X) = - 0.5

also,E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})

E(X^{2})  = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0
4 years ago
What is 62 take away 38 =​
Allushta [10]

Answer:

the answer is 24

Step-by-step explanation:

68-38 = 24

3 0
3 years ago
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Laura is a gourmet chef who runs a small catering business in a competitive industry. Laura specializes in making wedding cakes.
iren2701 [21]

Answer:

B.less cakes

Step-by-step explanation:

If she keeps making 20 cakes she will lose profit.

If she makes more she will lose profit.

She has to make less cakes to stop losing profits.

So the answer is B. Make less Cakes

7 0
3 years ago
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