3 years ago

What is the difference between consecutive numbers and consecutive odd numbers?

Mathematics

1 answer:

kirill [66]3 years ago

5 0

Yes that’s right have a nice day
Good luck!

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9. Using a twenty sided number cube, what is the probability that you will roll an even number or

IceJOKER [234]

Answer:

0.85

Step-by-step explanation:

total samples cases = 20

chances that are even or odd prime are 17 chances

2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20

probability = 17/20

= 0.85

3 0

2 years ago

Simplify the given expression, using only positive exponents. then complete the statements that follow. [ (x2y3)−1 (x−2y2z)2 ] 2

PolarNik [594]

[(x**-2) y**2 .z)**2]**2 (x**-8)(y**8)(z**4)
----------------------- = -----------------------------
[x**2 . y**3]**2 (x**4) (y**6)

(y**8)(z**4) (y**2)*(z**4)
--------------------- = -------------
(x**12) (y**6) (x**12)

7 0

3 years ago

Read 2 more answers

Three angles of a quadrilateral are 75°, 90° and 75°. What is the measure of the fourth angle?

Sergio039 [100]

the inside of quadrilateral is always 360°.So add 75°,90° and 75° and then subyaract from360°.

x+75°+75°+90°=360

×+240°=360°

x=360°-240°

x=120°

4 0

3 years ago

Arne sells furniture. He is paid a salary by his store if $800 a month plus a commission on all sales. Last month his sales were

devlian [24]

I don’t know yet I’m solving it sorry

5 0

3 years ago

Which is the equation of a hyperbola centered at the origin with y-intercepts +12 -12, and asymptote y=3x/2

dangina [55]

Answer:

$\frac{y^2}{144}-\frac{x^2}{64}=1$

Step-by-step explanation:

The equation of a hyperbola centered at the origin with vertices on the y-axis is given by: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

The vertices of the hyperbola are the y-intercepts (0,12) and (0,-12)

This implies that:

$2a=|12--12|$

$2a=24$

$a=12$

The asymptote equation of a hyperbola is given by:

$y=\pm\frac{a}{b}x$

The given hyperbola has asymptote: $y=\pm\frac{3}{2} x$

By comparison; $\frac{a}{b}=\frac{3}{2}$

$\implies \frac{12}{b}=\frac{12}{8}$

$\implies b=8$

The required equation is:

$\frac{y^2}{12^2}-\frac{x^2}{8^2}=1$

$\frac{y^2}{144}-\frac{x^2}{64}=1$

6 0

3 years ago

Read 2 more answers