Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
Answer:
1/16
Step-by-step explanation:
multiply the separate probabilities. On the number, it's 1/8 chance you'll get 1. On the letter, it's a 3/6 or 1/2 chance you'll get an A.
1/8 * 1/2 is 1/16.
If the probability of independent event A is 0.5, then P(A|B) will be 0.5. Then the correct option is B.
<h3>Which pair of events are called independent events?</h3>
When one event's occurrence or non-occurrence doesn't affect occurrence or non-occurrence of other event, then such events are called independent events.
Symbolically, we have:
Two events A and B are said to be independent iff we have:
P(A ∩ B) = P(A)P(B)
Comparing it with chain rule will give
P(A|B) = P(A)
P(B|A) = P(B)
Suppose A and B are dependent events.
If P(A) = 0.5
Then P(A|B) will be
P(A|B) = P(A)
P(A|B) = 0.5
Then the correct option is B.
Learn more about probability here:
brainly.com/question/1210781
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Answer:
25 y 3−15 y 2−10 y ... 25y3 - 15y2 - 10y = 5y • (5y2 - 3y - 2) ... 5y • (y-1) Add up the last 2 terms, pulling out common factors : 2 • (y-1
